**Molarity Calculations Examples**

**Molarity Calculation Problem Example **: If one mole of
potassium
chloride (74.55g/mole) is dissolved in 1dm^{3}_{ }of
solution,
the result is a one molar solution of potassium chloride.

**Molarity Calculation Problem Example 2**: If half a mole
of potassium
chloride is dissolved in 1dm^{3} of solution, the result is a
0.5
molar solution of potassium chloride.

**Molarity Calculation Problem Example 3**: If 0.217 mole
of potassium
chloride is dissolved in 5dm^{3} of solution, the result is a
(0.217mole)/5dm^{3} = 0.0437 molar solution of potassium
chloride.

**Molarity Calculation Problem Example 4**: If 105.45 grams
of potassium
chloride (74.55g/mole) is dissolved in 2dm^{3}_{ }of
solution,
the result is (105.45g/(74.55g/mole))/2dm^{3} = 0.707 molar
solution
of potassium chloride.

**NOTE:** *Water is added to the volumetric flask up to the
one liter
line*.

**CHEMIX solution **- **Molarity Calculations -
Example 4**

In **Molecular Calculator** insert **105.45gKCl**
in the
**formula** text field and **Calculate**. Then divide the
resulting
mole amount in **Calculated values** by two (2dm^{3}).
1.41mol/2dm^{3} = 0.707 molar
solution
of potassium chloride.