CHEMIX School concentration and dilution calculator allow efficient dilution calculations. A minimal amount of steps is needed for this kind of calculations.

It is possible to use molar, molal, w/w%, w/v% or mole fraction (x) stock concentrations .

Useful formulas:

Knowing that the density of a 17.4M CH_{3}COOH
solution = 1.05148 g/mL

a) How many mL of a 17.4M a acetic acid stock solution is needed for making 3500 mL of a 2M acetic acid solution.

b) How many grams of a 17.4M a acetic acid stock solution is needed for making 3500 mL of a 2M acetic acid solution.

We know that: M =**n/V**_{solution}
**
C**_{1}** V**_{1}**
= C**_{2}** V**_{2}**
**(dilution formula)

**Solution a)**

17.4M * C_{2} = 3.5L
* 2M

a) How many mL of a 17.4M a acetic acid stock solution is needed for making 3500 mL of a 2M acetic acid solution.

b) How many grams of a 17.4M a acetic acid stock solution is needed for making 3500 mL of a 2M acetic acid solution.

We know that: M =

17.4M * C

V_{2} = (3.5L * 2M)/17.4M =
0.4023 L = 402.3mL

**Solution b)**

Since we already know** (**from solution a) **)**
the volume of a 17.4M solution needed and the density
we can calculate the mass :

We need to measure out 402.3mL * 1.05148 g/mL= 423.01g of 17.4M acetic acid

Since we already know

We need to measure out 402.3mL * 1.05148 g/mL= 423.01g of 17.4M acetic acid

1) Select acetic acid (

2) Insert 17.4 and select Molar in the

3) Insert V

4) Insert 2 in the

******** Dilution by volume ********

Put about 2000 mL of water into a flask and add 402.299 mL acetic acid stock conc. Add water until 3500 mL

******** Dilution by mass ********

Put about 2000 g of water into a flask and add 423.009 g of acetic acid stock conc. Add water until 3553.06 g

Prepare 200mL of a 2 molal solution by diluting a 5 Molar sodium chloride solution.

FW

Convert from molal to molar and solve the problem using:

Molarity of a 2molal solution (using 1Kg solvent for simplicity):

m= n/m

Volume of solution: V

M = n/V

V

Prapare a 2 molal (

1) Select sodium chloride (

2) Insert stock concentration = 5 and select

3) Insert V

4) Insert 2 in the

******** Dilution by volume ********

Put about 90 mL of water into a flask and add 76.9404 mL sodium chloride stock conc. Add water until 200 mL

******** Dilution by mass ********

Put about 90 g of water into a flask and add 91.2324 g of sodium chloride stock conc. Add water until 214.834 g

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